Design with Operational Amplif

Design with Operational Amplifiers and Analog Integrated Circuits –3rd Edition

Design with Operational Amplifiers and Analog Integrated Circuits – 3rd Edition
Sergio Franco - McGraw-Hill, 2002 - ISBN 0-07-232084-2
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First-Printing Errata (Updated May 20, 2007)
Page 47, Problem 1.3, 1st line: change Aoc to Ar
Page 104, Fig. P2.54: swap the resistance labels R and )1(δ+R
Page 113, Eq. (3.11a): change ?H1???H2? to ?H1?/?H2?
Page 114, Eq. (3.13c): change ?1/H1?dB to ?1/H?dB
Page 137, Example 3.11, Solution (b): change 136.69° to ?136.69° (twice), and 46.69°
to 133.31° (twice)
Page 145, denominator of the right-hand side of the equation following Eq. (3.78): replace + R4(1 + with + R4R7C2(1 +
Page 162, Fig. 4.2b: change arrow as shown on the r ight:
age 162, text preceding Eq. (4.2): change b2 to b1, and replace b3 with b2 = b3
P
Page 205, Problem 4.8, 2nd line from the end: change 11.080 Hz to 11.080 kHz
Page 285, Eq. (6.38), last denominator term: change –(f/ft)4 to +(f/ft)4
Page 295, 2nd line: change –10 dec/dec to –1 dec/dec
Page 351, last line: change (5 – 1) to (5 – 2) Page 352, right edge of Fig. 8 (b): chan 45° t .4 ge o –45°
R1/R2)/2πR2Cf
πR2Cf ? 210 kHz;
Page 3 Problem 8.48; Example 8.16,
Page 3 a10(
e text 5 lines below: change exp[(t – t0)
Page 5 line: change VBE3(on)/(R3 + R4) to VBE3(on)/R4; 4th line: change
Page 5 to tOFF/2 with to tON + tOFF/2; Eq. (11.48):
Page 358, Fig. 8.9: swap + and ? inside the op amp
Page 362, Solution: change fx = 107/( to fx = 2×107/(
Page 363, after Eq. (8.20a): change 1/2πR2Cf to (1 +
Page 364, Solution (b): change 1/2πR2Cf ? 140 kHz to (1 + R1/R2)/2
in the denominator of A(jf), change 140 to 210
85, line after Eq. (8.36): change Problem 8.46 to
second line: change 99 k to 99 kΩ
86, 4th line: change a0 = a01( to a0 =
Page 451, expression after Eq. (10.2), and in th
to exp[–(t – t0)
22, Solution, 3rd
160 Ω to 210 Ω, and 540 Ω to 700 Ω
41, 3rd line before Eq. (11.46): replace
change numerator from IO(1 – VI/VO) to IO/(1 – VI/VO)