數(shù)字電子技術(shù)基礎(chǔ)(閻石第四版課后習(xí)題答案詳解)

1.1 二進(jìn)制到十六進(jìn)制、十進(jìn)制
(1)(10010111)2=(97)16=(151)10 (2)(1101101)2=(6D)16=(109)10
(3)(0.01011111)2=(0.5F)16=(0.37109375)10 (4)(11.001)2=(3.2)16=(3.125)10
1.2 十進(jìn)制到二進(jìn)制、十六進(jìn)制
(1)(17)10=(10001)2=(11)16 (2)(127)10=(1111111)2=(7F)16
10 2 16 10 2 16 (3) (0.39) = (0.0110 0??011 1101 0111 0000 1010??) = (0.63??D70A?? ) (4) (25.7) = (11001.1011 0??011??) = (19.B3??)
1.8 用公式化簡邏輯函數(shù)
(1)Y=A+B (3)Y=1
解： （1 A＋A＝1）
(2)
= + + + = + + + =
= + + +
Y BC A B C C A B C
Y ABC A B C
AD BC B C AD B C C AD
Y ABCD ABD ACD
= + + = + + =
= + +
Y ( ) ( )
(4)
解：
(5)Y=0 (7)Y=A+CD
Y BC B AD CE BC B AD CE ABCD C E ABCDE
Y AC CD AB BC B AD CE
= ? + = + ? = + =
= + + + +
( ) ( ) ( )
(6) ( ) ( )
解：
A BC A B C A ABC BC A BC
Y A B C A B C A B C A ABC BC A B C
Y A B C A B C A B C
= + + + = + + = +
= + ? + + + + = + + + +
= + + + + + +
( )
( )( )( ) ( )( )
8 ( )( )( )
解：
（ ）
(9)Y = BC + AD + AD (10)Y = AC + AD+ AEF + BDE + BDE
1.9 (a) Y = ABC + BC (b) Y = ABC + ABC
(c) Y = AB + ACD Y = AB + ACD + ACD + ACD 1 2 ,
(d) Y = AB + AC + BC Y = ABC + ABC + ABC + ABC 1 2 ,
1.10 求下列函數(shù)的反函數(shù)并化簡為最簡與或式